ALL JEE 2026 January PYQs | Straight Lines | JEE Mains Questions Chapter Wise
Understanding Straight Line Questions
Introduction to Straight Line Problems
- The discussion focuses on solving straight line questions, which are often lengthy and complicated, making it challenging to determine the approach.
- The session aims to teach strategies for using geometry effectively in these problems, particularly through examples from JEE Mains 2026.
First Problem Overview
- The first question involves a point located between two parallel lines L1 and L2, with specified distances from each line.
- An equilateral triangle ABC is formed where point B lies on line L1 and point C on line L2; the area of this triangle needs to be calculated.
Geometry Setup
- Points are assigned: A is the midpoint between L1 and L2, with known distances (6 units from L1 and 3 units from L2).
- The angles of triangle ABC are established as 60° each due to its equilateral nature, leading to equal side lengths AB, BC, and AC.
Area Calculation Methodology
- To find the area of triangle ABC, one must derive the length of any side using geometric principles.
- By introducing an angle θ at point A and establishing relationships between sides using trigonometric identities like cos(θ), calculations can proceed.
Solving for Side Lengths
- Using right triangles formed by dropping perpendicular lines helps express side lengths in terms of θ.
- Equating expressions for sides AB and AC leads to a relationship that simplifies down to finding cos(θ).
Trigonometric Relationships
Deriving Cosine Values
- Establishing that cos(θ + 120°)=2cos allows for further simplification in determining θ's value.
- Utilizing cosine values such as cos(120°), which equals -1/2, aids in calculating necessary trigonometric ratios.
Final Area Computation
- After deriving tan values based on previous calculations, one can compute the area using standard formulas involving base and height.
Statement Type Scenarios
Evaluating Statements about Triangles
- The next problem presents two statements regarding points A and B forming a triangle with an orthocenter; verification is required if these points satisfy certain conditions.
Orthocenter Calculation Steps
- To find the orthocenter D of triangle ABC, perpendicular lines from vertices A and B need their equations derived based on slopes.
Rectangle Formation
Rectangle Defined by Lines
- Another question describes a rectangle formed by four given lines intersecting at specific coordinates.
Perpendicular Line Analysis
- A new line l is introduced that divides the rectangle into equal parts; its slope must be determined based on existing lines' slopes.
Rhombus Properties
Diagonal Points in Rhombus
- In another scenario involving a rhombus defined by diagonal points A and C along with parallel sides AD and BC.
Midpoint Calculations
- Finding midpoints helps establish relationships among vertices crucial for solving related queries about sums or coordinates.
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Understanding the Length of AD
Calculation of Length
- The length of segment AD is determined to be 4, derived from the equation 4/3 = AD/3 .
- By substituting values into the equation, we find that alpha + 8beta - 4 = 12 , leading to a simplified form of 9alpha - 4 = 12 .
Solving for Alpha and Beta
- Adding terms results in 9alpha = 16beta , which simplifies to give a value for beta as 32/9 .
- Conversely, subtracting yields 9alpha = -8 , resulting in an alpha value of -8/9 .
Analyzing Triangle Orientation
Positioning Points
- The triangle's orientation indicates that both points must lie on the same side relative to the origin; negative outputs suggest incorrect positioning.
- If alpha and beta are placed incorrectly, it could lead to contradictions regarding their positions.
Validating Values
- Substituting values back into equations confirms whether they yield positive or negative outputs; this helps validate if both points are correctly positioned.
Finalizing Alpha and Beta Values
Confirming Results
- After checking calculations with substituted values, we confirm that alpha equals -8/9 and beta equals -32/9 .
Conclusion on Integer Values
Greatest Integer Function Application
- Applying the greatest integer function leads us to conclude that the final answer is four when considering all calculated values.
Summary of Problem-Solving Approach
Review of Methodology
- The approach taken reflects effective problem-solving strategies used in JEE Main questions related to straight lines. Further resources can be explored for additional practice.
Additional Resources
Exploring More Chapters
- Viewers are encouraged to check out other chapters available in playlists for comprehensive learning on related topics.
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