*Columna de absorción: Balance de materia: Problema 2....Parte II

*Columna de absorción: Balance de materia: Problema 2....Parte II

New Section

In this section, the speaker discusses calculations related to excess water percentage in a material balance context.

Calculating Excess Water Percentage

  • The excess water percentage is determined by dividing the operating flow by the minimum flow to remove excess, resulting in a value greater than one. Subtracting one gives a fraction that, when multiplied by 100, yields the excess.
  • Different methods exist for graphing based on factors like Henry's law constants and saturation compressions.
  • Equating Henry's law with Dalton's law is crucial when working with two phases (gas and liquid).
  • The equilibrium mol fraction of the liquid phase can be calculated using Henry's constant and other relevant parameters.

New Section

This section delves into graphing techniques and considerations for absorption processes.

Graphing Techniques for Absorption

  • Absorption process boundaries are defined by upper and lower limits represented by uppercase or lowercase Y values.
  • Calculations involving various x values are performed to determine concentrations at different points along the curve.
  • Identifying concavity helps locate points of interest on the graph for analysis.

New Section

Here, the focus shifts to determining maximum values and analyzing equilibrium curves in absorption processes.

Analyzing Equilibrium Curves

  • Locating points of interest such as x-values corresponding to specific concentrations aids in understanding absorption dynamics.
  • Drawing tangents to curves allows for identifying maximum values accurately based on equilibrium conditions.

New Section

In this section, the speaker discusses the process of converting a relationship into a mathematical equation and solving it graphically.

Converting Relationship to Equation

  • The relationship is converted into a mathematical equation by substituting variables.
  • After substituting in the equation of the line, the x variable is isolated.
  • By isolating x, the result is obtained.

New Section

This part focuses on graphically finding the intersection point to determine the result.

Graphical Intersection Point

  • The intersection point is found by graphing without plotting it.
  • Once located, the intersection point is tested to obtain the final result.

New Section

Here, horizontal positioning and graphical representation are discussed for further calculations.

Horizontal Positioning and Graphical Representation

  • Horizontal positioning involves locating specific points on the graph.
  • The point 1 is traced horizontally to point 2 to establish an operational line.

New Section

This segment delves into identifying and converting lowercase variables to uppercase for further analysis.

Identifying Variables and Conversion

  • The operational line guides in identifying lowercase variables that need conversion.
  • Lowercase variables are transformed into uppercase for consistency in calculations.

New Section

Exploring how known values guide in determining unknown variables along with their conversions.

Determining Unknown Variables

  • Known values assist in determining unknown variables along a given operational line.
Video description

En una refinería se requiere limpiar el aire contaminado con SO2 para lo que se emplea agua libre de SO2, los fluidos se ponen en contacto en una columna empacada con los flujos en arreglo en contracorriente. La columna trabaja en forma isotérmica a 30ºC e isobáricamente a 1.3 atmosferas. Por la base de la columna se alimenta una mezcla de aire- SO2 a razón 514.61 kg/h y con una presión parcial del SO2 de 91.2 mm Hg. A la salida el gas no debe contener más de 11.7 mg/L. Por el domo de la columna se alimenta un gasto tal de agua que cada kilogramo de SO2 se recupera con 1.66 kg de agua. El sistema sigue la Ley de Henry, donde la constante es de 0.548 atm/fracción mol. Los pesos moleculares son: 64 para el SO2, 18 para el agua y 29 para el aire. La gravedad específica de la solución acuosa a cualquier concentración se puede considerar de 0.981. Determinar * Porcentaje de exceso de agua con el que se trabaja. * ¿Cuál es la relación peso del líquido que está en contacto con el gas que tiene una composición de 5.66% mol en la columna. https://sites.google.com/site/profgzacahua/cursos