MÁXIMOS, MÍNIMOS O PUNTOS DE SILLA. HESSIANO. Ejemplo 1. Video#135
Critical Points of a Function of Two Variables
Introduction to Critical Points
- The video introduces the concept of determining critical points for functions of two variables, aiming to classify them as local maxima, minima, or saddle points.
Problem Statement
- The function given for analysis is f(x,y) = x^2 + y^2 - 5x - 4y + xy . The task is to find its critical points and classify them.
Finding Partial Derivatives
- To find critical points, the process begins similarly to single-variable functions: derive the function and set it equal to zero.
- The first step involves calculating partial derivatives with respect to x and y .
Derivative with Respect to x
- For the partial derivative with respect to x , treat all other variables as constants. This results in:
- f_x = 2x - 5 + y .
Derivative with Respect to y
- Similarly, for the partial derivative with respect to y :
- f_y = 2y - 4 + x .
Setting Up Equations
- Next, both partial derivatives are set equal to zero:
- From f_x = 0: quad 2x - 5 + y = 0
- From f_y = 0: quad x + 2y - 4 = 0
Solving for Critical Points
- These equations form a system that can be solved simultaneously. Rearranging gives:
- First equation: y = 5 - 2x
- Second equation becomes: substituting into it leads us towards finding values for both variables.
Calculation Steps
- By manipulating these equations (multiplying one by two), we simplify and solve for values leading us toward identifying critical points.
Identifying Critical Point Values
- After calculations, we find a critical point at coordinates (2,1).
Classifying Critical Points Using Hessian Determinant
- To determine if this point is a maximum, minimum, or saddle point, we use the Hessian determinant defined as:
- D = f_xxf_yy - (f_xy)^2 .
Importance of Hessian Determinant
- Understanding how this determinant works will help classify our found critical point based on its value relative to zero.
Finding Second Derivatives and Critical Points
Steps to Calculate Second Derivatives
- The process begins with finding the second derivatives of a function, specifically focusing on f_xx , which involves taking the derivative of f_x again with respect to x .
- The first derivative yields 2x , while the derivatives of constants result in zero. Thus, we have established f_xx = 2 .
- Next, we calculate f_yy , which is the second derivative with respect to y . This results in a constant value of 2 for the term involving x , while other terms yield zero.
Substituting Values into Determinant Expression
- After determining both second derivatives, we substitute these values into a determinant expression. Here, it simplifies to calculating 4 - 1^2 = 3 .
- The determinant being greater than zero indicates that we are in a specific category concerning critical points.
Analyzing Critical Points
- With the determinant calculated as 3 (greater than zero), further analysis shows that if either condition holds true ( f_xx > 0), it confirms our findings.
- Conclusively, since both conditions are satisfied (determinant > 0 and f_xx > 0), this indicates that the critical point identified is indeed a minimum.
Conclusion